2.91x^2-2.108+.04=0

Solution for 2.91x^2-2.108+.04=0 equation:

2.91x^2-2.108+.04=0

We add all the numbers together, and all the variables

2.91x^2-2.068=0

a = 2.91; b = 0; c = -2.068;
Δ = b2-4ac
Δ = 02-4·2.91·(-2.068)
Δ = 24.07152
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{24.07152}}{2*2.91}=\frac{0-\sqrt{24.07152}}{5.82}
=-\frac{\sqrt{}}{5.82}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{24.07152}}{2*2.91}=\frac{0+\sqrt{24.07152}}{5.82}
=\frac{\sqrt{}}{5.82}
$